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In the figure, $ABCD$ and $PQRC$ are rectangles and $Q$ is the mid-point of $AC$.
Prove that $DP = PC$.
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Academic Mathematics NCERT Class 9

Given:

$ABCD$ and $PQRC$ are rectangles and $Q$ is the mid-point of $AC$.

To do:

We have to prove that $DP = PC$.

Solution:

In $\triangle ACD$,

$Q$ is the mid-point of $AC$ and $QP \parallel AD$.

This implies,

$P$ is the mid-point of $CD$.

Therefore,

$DP = PC$

Hence proved.

Updated on: 10-Oct-2022

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