In the adjoining figure, $SP$ and $RQ$ are perpendiculars on the same line $PQ$. Prove that $\Delta P Q S \cong \Delta Q P R$.
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Given :
In the given figure, $SP$ and $RQ$ are perpendiculars on the same line $PQ$.
To do :
We have to prove that, $\Delta P Q S \cong \Delta Q P R$.
Solution :
$SP = RQ = 5 cm$
$∠SPQ = ∠RQP = 90°$
In $△SPQ$ and $△RQP$,
$PS = RQ = 5 cm$
$∠SPQ = ∠RQP$
$PQ = PQ$ (Common side)
Therefore, by SAS congruency
$\Delta P Q S \cong \Delta Q P R$
Hence Proved.
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