In the adjoining figure $AB =AD$ and $CB =CD$ Prove that $\vartriangle ABC\cong\vartriangle ADC$
"
Given: $AB=AD$ and $CB=CD$
To do: To prove that $\vartriangle ABC\cong\vartriangle ADC$
Solution:
In $\vartriangle ABC$ and $\vartriangle ADC$,
$AB=AD$ and $CD=CB$ $( Given)$
$AC=AC$ $( Common)$
So, according to SSS congruency rule,
$\vartriangle ABC\cong\vartriangle ADC$
$\vartriangle ABC$ is congruent to $\vartriangle ADC$.
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