"
">

In figure below, $Δ\ ACB\ ∼\ Δ\ APQ$. If $BC\ =\ 8\ cm$, $PQ\ =\ 4\ cm$, $BA\ =\ 6.5\ cm$ and $AP\ =\ 2.8\ cm$, find $CA$ and $AQ$.

"

Academic Mathematics NCERT Class 10

Given:

In the given figure $Δ\ ACB\ ∼\ Δ\ APQ$.

$BC\ =\ 8\ cm$, $PQ\ =\ 4\ cm$, $BA\ =\ 6.5\ cm$ and $AP\ =\ 2.8\ cm$.

To do:

We have to find the value of $CA$ and $AQ$.

Solution:

$Δ\ ACB\ ∼\ Δ\ APQ$ (given)

Therefore,

$\frac{BA}{AQ} = \frac{CA}{AP} = \frac{BC}{PQ}$ (Corresponding parts of similar triangles are proportional)

$\frac{6.5}{AQ} = \frac{8}{4}$

$AQ = \frac{6.5 \times 4}{8}$

$AQ = 3.25\ cm$

And,

$\frac{CA}{AP} = \frac{BC}{PQ}$

$\frac{CA}{2.8} = \frac{8}{4}$

$CA = 2.8 \times 2$

$CA = 5.6\ cm$

Hence, the values of $CA$ and $AQ$ are $5.6\ cm$ and $3.25\ cm$ respectively.

Updated on: 10-Oct-2022

35 Views

Kickstart Your Career

Get certified by completing the course

Advertisements