In figure below, AD bisects $\angle A$, $AB=12\ cm, AC=20\ cm$ and $BD=5\ cm$, determine CD. "
Given:
AD bisects $\angle A$, $AB=12\ cm, AC=20\ cm$ and $BD=5\ cm$.
To do:
We have to determine CD.
Solution:
We know that,
The internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the corresponding sides containing the angle. Therefore,
$\frac{AB}{AC}=\frac{BD}{DC}$
$\frac{12}{20}=\frac{5}{CD}$
$CD=\frac{5\times20}{12}$
$CD=\frac{5\times5}{3}$
$CD=\frac{25}{3}$
$CD=8.33\ cm$
The length of $CD$ is $8.33\ cm$.
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