In figure 2, $\vartriangle$AHK is similar to $\vartriangle$ABC
. If AK$=10$ cm
Given: In fig. 2, $\vartriangle AHK\sim \vartriangle ABC$ , AK$=10$ cm, BC$=3.5$ cm.
To do: To find out AC.
Solution:
As given $\vartriangle AHK\sim \vartriangle ABC$
$\Rightarrow \ \frac{AH}{AB} =\frac{HK}{BC} =\frac{AK}{AC}$
$\Rightarrow \ \frac{HK}{BC} =\frac{AK}{AC}$
On subtituting the value $AK=10\ cm,BC=3\ cm\ and\ HK=3$ cm
$\Rightarrow \ \frac{7}{3.5} =\frac{10}{AC}$
$\ \Rightarrow \ AC=\frac{10\times 3.5}{7}$
$\Rightarrow \ AC=5$ cm
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