In Fig.5. PSR, RTQ and PAQ are three semicircles of diameters 10 cm, 3 cm and 7 cm respectively. Find the perimeter of the shaded region. [Use $\pi = 3.14$] "
Given: In Fig.5. PSR, RTQ and PAQ are three semicircles of diameters $10\ cm$, $3\ cm$ and $7\ cm$ respectively.
To do: To find the perimeter of the shaded region.
Solution:
Radius of Semicircle PSR= $\frac{1}{2}$ x 10 =5 cm
Radius of Semicircle RTQ =$\frac{1}{2}$x 3 = 1.5 cm
Radius of semicircle PAQ =$\frac{1}{2}$x 7 = 3.5 cm \
Circumference of the semi-circle PSR=$\pi \times 5=5\pi \ cm$
Circumference of the semi-circle RTQ=$\pi \times 1.5=1.5\pi \ cm$
Circumference of the semi-circle PAQ =$\pi \times 3.5=3.5\pi \ cm$
Perimeter of the shaded region = Circumference of semicircle PSR+ Circumference of semicircle RTQ+ Circumference of semicircle PAQ
=$5\pi \ cm$+$1.5\pi \ cm$+$3.5\pi \ cm$
=10$\pi $
=10$\times $3.14
=31.4 cm
Therefore, perimeter of the shaded region is $31.4\ cm$.
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