In a circle of radius \( 6 \mathrm{~cm} \), a chord of length \( 10 \mathrm{~cm} \) makes an angle of \( 110^{\circ} \) at the centre of the circle. Find the area of the circle.

Given:

Radius of the circle $r=6 \mathrm{~cm}$.

Length of the arc $l=10 \mathrm{~cm}$.

Angle subtended at the centre $=110^{\circ}$.

To do:

We have to find the area of the circle.

Solution:

Let $OA$ and $OB$ are the radii of the circle and $AB$ the chord.

We know that,

Area of a circle of radius $r$ is $\pi r^2$.

Therefore,

Area of the circle $=3.14 \times 6 \times 6\ cm$

$=113.04\ cm^2$

The area of the circle is $113.04\ cm^2$.

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Updated on: 10-Oct-2022

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