In a circle of radius \( 21 \mathrm{~cm} \), an arc subtends an angle of \( 60^{\circ} \) at the centre. Find the length of the arc. (Use \( \pi=22 / 7 \) )

Given:

Radius of the circle $r=21 \mathrm{~cm}$.

Angle subtended by the arc $=60^{\circ}$

To do:

We have to find the length of the arc.

Solution:

Let the length of the arc be $l$.

We know that,

Length of arc $=2 \pi r(\frac{\theta}{360^{\circ}})$

Therefore,

Length of the arc $l=2 \times \frac{22}{7} \times 21 \times \frac{60^{\circ}}{360^{\circ}} \mathrm{cm}$

$=132 \times \frac{1}{6} \mathrm{cm}$

$=22 \mathrm{cm}$

The length of the arc is $22 \mathrm{~cm}$.

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Updated on: 10-Oct-2022

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