In a $Δ\ ABC$, $D$ and $E$ are points on the sides $AB$ and $AC$ respectively such that $DE\ ||\ BC$. If $\frac{AD}{BD}\ =\ \frac{4}{5}$ and $EC\ =\ 2.5\ cm$, find $AE$. "
Given:
In a $Δ\ ABC$, $D$ and $E$ are points on the sides $AB$ and $AC$ respectively such that $DE\ ||\ BC$.
$\frac{AD}{BD}\ =\ \frac{4}{5}$ and $EC\ =\ 2.5\ cm$.
To do:
We have to find the measure of $AE$.
Solution:
$DE\ ||\ BC$ (given)
Therefore,
By Basic proportionality theorem,
$\frac{AD}{BD}\ =\ \frac{AE}{CE}$
$\frac{4}{5}=\frac{AE}{2.5}$
$AE=\frac{4\times2.5}{5}$
$AE=\frac{10}{5}$
$AE=2 cm$
The measure of $AE$ is $2 cm$.
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