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In a $Δ\ ABC$, $D$ and $E$ are points on the sides $AB$ and $AC$ respectively such that $DE\ ||\ BC$.
If  $\frac{AD}{BD}\ =\ \frac{4}{5}$  and  $EC\ =\ 2.5\ cm$, find $AE$.

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Given:


In a $Δ\ ABC$, $D$ and $E$ are points on the sides $AB$ and $AC$ respectively such that $DE\ ||\ BC$.

$\frac{AD}{BD}\ =\ \frac{4}{5}$ and $EC\ =\ 2.5\ cm$.

To do:


We have to find the measure of $AE$.

Solution:


$DE\ ||\ BC$ (given)

Therefore,

By Basic proportionality theorem,

$\frac{AD}{BD}\ =\ \frac{AE}{CE}$

$\frac{4}{5}=\frac{AE}{2.5}$

$AE=\frac{4\times2.5}{5}$

$AE=\frac{10}{5}$

$AE=2 cm$

The measure of $AE$ is $2 cm$.

Updated on: 10-Oct-2022

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