![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
If $x^3-4x^2 + 19 = 6 ( x-1)$, then what is the value of $[x^2 + (\frac{1}{( x-4)}]$.
Given: Expression: $x^3 – 4x^2 + 19 = 6 (x – 1)$.
To do: To find the value of $[x^2+(\frac{1}{( x-4)}]$.
Solution:
Given expression: $x^3-4x^2+19=6( x-1)$
$\Rightarrow x^3-4x^2+1+18=6x-6$
$\Rightarrow x^3-4x^2+1=6x-24$
$\Rightarrow x^3-4x^2+1=6(x-4)$ ...... $( i)$
$x^2+\frac{1}{( x-4)}=\frac{x^2( x-4)+1}{( x-4)}=\frac{( x^3-4x^2+1)}{( x-4)}$
From equation $( i)$
$\frac{( x^3-4x^2+1)}{( x-4)}=\frac{6( x-4)}{( x-4)}=6$
$\therefore x^2+\frac{1}{( x-4)}=6$
Advertisements