- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
If the speed of a body is halved, what will be the change in its kinetic energy?
We know the equation of the kinetic energy$K=\frac{1}{2}mv^2$
Here, $K\rightarrow$ kinetic energy of the body
$m\rightarrow$ mass of the body
$v\rightarrow$ velocity of the body
If the velocity of the body is halved, then it becomes $\frac{v}{2}$
Then kinetic energy of the body $K'=\frac{1}{2}m(\frac{v}{2})^2$
Or $K'=\frac{1}{4}\times\frac{1}{2}mv^2$
Or $K'=\frac{K}{4}$
Thus, when the velocity of a moving body is halved the kinetic energy becomes one-fourth of its kinetic energy.
Advertisements