If the point $(2, -2)$ lies on the graph of the linear equation $5x + ky =4$, find the value of $k$.
Given:
The point $(2, -2)$ lies on the graph of the linear equation $5x + ky =4$
To do:
We have to find the value of $k$.
Solution:
The point $(2, -2)$ lies on the graph of the linear equation $5x + ky =4$.
This implies,
$(2, -2)$ satisfies the equation $5x + ky =4$.
Therefore,
$5(2)+k(-2)=4$
$10-2k=4$
$2k=10-4$
$2k=6$
$k=\frac{6}{2}$
$k=3$
The value of $k$ is $3$.
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