If the pth term of an A.P. is $(2p+3)$, find the A.P.
Given :
pth term of an A.P. = $(2p+3)$
To find :
We have to find the A.P
Solution :
p1=$2(1)+3=2+3=5$
p2=$2(2)+3=4+3=7$
p3=$2(3)+3=6+3=9$
.
.
.
.
Therefore, the required A.P. is 5,7,9.......
Related Articles
- If the 5th term of an A.P. is 31 and 25th term is 140 more than the 5th term, find the A.P.
- The 7th term of an A.P. is 32 and its 13th term is 62. Find the A.P.
- The 19th term of an A.P. is equal to three times its sixth term. If its 9th term is 19, find the A.P.
- The 9th term of an A.P. is equal to 6 times its second term. If its 5th term is 22, find the A.P.
- The 17th term of an A.P. is 5 more than twice its 8th term. If the 11th term of the A.P. is 43, find the nth term.
- The first term of an A.P. is 5 and its 100th term is $-292$. Find the 50th term of this A.P.
- If 10 times the 10th term of an A.P. is equal to 15 times the 15th term, show that 25th term of the A.P. is zero.
- If the nth term of the A.P. $9, 7, 5, …$ is same as the nth term of the A.P. $15, 12, 9, …$ find $n$.
- In an A.P. the sum of $n$ terms is $5n^2−5n$. Find the $10^{th}$ term of the A.P.
- Which term of the A.P. $3, 8, 13, ……$ is $248$?
- Is 302 a term of the A.P. $3, 8, 13, …..$?
- The sum of first n terms of an A.P. is $5n – n^2$. Find the nth term of this A.P.
- The sum of first n terms of an A.P. is $3n^2 + 4n$. Find the 25th term of this A.P.
- Find:18th term of the A.P. $\sqrt2, 3\sqrt2, 5\sqrt2, ……….$
- The sum of the first n terms of an A.P. is $3n^2 + 6n$. Find the nth term of this A.P.
Kickstart Your Career
Get certified by completing the course
Get Started