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If the length and breadth of a rectangle are doubled, how many times the perimeter of old rectangle will that of new rectangle?
Given:
The length and breadth of a rectangle are doubled.
To do:
We have to find how many times the perimeter of old rectangle will that of new rectangle.
Solution:
Let the length of the original rectangle be 'l' and breadth of the rectangle be 'b'.
Perimeter of old rectangle $= 2(l+b)$.
Length of the rectangle is doubled
So, length of new rectangle $= 2l$
Breadth of the rectangle is doubled
So, breadth of new rectangle $= 2b$
Perimeter of new rectangle $= 2(2l+2b)=2[2(l+b)]$
Perimeter of new rectangle $= 2(Perimeter\ of\ original\ rectangle)$
Perimeter of new rectangle becomes 2 times the perimeter of the old rectangle.
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