If $P(E)= 0.005$, then find out $\displaystyle P(\overline{E})$
Given :
$P(E) = 0.005$
To find :
We have to find $\displaystyle P(\overline{E})$
Solution :
We know that,
$\displaystyle P(\overline{E}) = 1-P(E)$
$= 1-0.005$
$=1.000-0.005$
$=0.995$.
$\displaystyle P(\overline{E})$ is $0.995$
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