If $\frac{x}{4}=\frac{3}{6}$, find the value of $x$.
Given:
$\frac{x}{4}=\frac{3}{6}$
To do:
We have to find the value of $x$.
Solution:
$\frac{x}{4}=\frac{3}{6}$
$x=4\times\frac{3}{6}$
$x=\frac{12}{6}$
$x=2$
The value of $x$ is $2$.
Related Articles
- If \( x^{4}+\frac{1}{x^{4}}=119 \), find the value of \( x^{3}-\frac{1}{x^{3}} \).
- If $\frac{3}{4}(x-1)=x-3$, find the value of $x$.
- Find the value of $x$$\frac{8}{-3}= \frac{x}{6}$
- If $( \frac{( 3 x-4)^{3}-( x+1)^{3}}{( 3 x-4)^{3}+( x+1)^{3}}=\frac{61}{189})$, find the value of $x$.
- Find the value of $\frac{x}{y}$ if $(\frac{3}{5})^{4}$ $\times$ $(\frac{15}{10})^{4}$=$(\frac{x}{y})^{4}$
- If $x + \frac{1}{x} = 9$ find the value of $x^4 + \frac{1}{x^4}$.
- If \( x+\frac{1}{x}=5 \), find the value of \( x^{3}+\frac{1}{x^{3}} \).
- If \( x-\frac{1}{x}=7 \), find the value of \( x^{3}-\frac{1}{x^{3}} \).
- If \( x-\frac{1}{x}=5 \), find the value of \( x^{3}-\frac{1}{x^{3}} \).
- If $\frac{x}{3}=\frac{2}{7}$, find the value of $x$.
- Find the value of $x$$\frac{x+2}{2}- \frac{x+1}{5}=\frac{x-3}{4}-1$
- Take away:\( \frac{6}{5} x^{2}-\frac{4}{5} x^{3}+\frac{5}{6}+\frac{3}{2} x \) from \( \frac{x^{3}}{3}-\frac{5}{2} x^{2}+\frac{3}{5} x+\frac{1}{4} \)
- If \( x^{4}+\frac{1}{x^{4}}=194 \), find \( x^{3}+\frac{1}{x^{3}}, x^{2}+\frac{1}{x^{2}} \) and \( x+\frac{1}{x} \)
- If $x - \frac{1}{x} = 3$, find the values of $x^2 + \frac{1}{x^2}$ and $x^4 + \frac{1}{x^4}$.
- Find the value of $x^2+\frac{1}{x^2}$ if $x+\frac{1}{x}=3$.
Kickstart Your Career
Get certified by completing the course
Get Started