If $\frac{a_1}{a_2}≠\frac{b_1}{b_2} $, then how many solutions will the system of equations $a_1x+b_1y=c_1$ and $a_2x+b_2y=c_2$?
Solution:
 
Given equations are:$a_1x+b_1y=c_1$ and $a_2x+b_2y=c_2$
For $\frac{a_1}{a_2}≠\frac{b_1}{b_2}$, the given system of linear equations will have a one and unique solution.
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