If \( a=2, b=3 \) and \( c=4, \) then find the value of \( 3 a-b+c \).

Given: $a=2, b=3$ and $c=4$.

To do: To find the value of $3a-b+c$.

Solution:

$\because a=2, b=3$ and $c=4$

On substituting these value in $3a-b+c$, we have

$3a-b+c=3( 2)-3+4$

$=6-3+4$

$=10-3$

$=7$

$\therefore$, The value of $3a-b+c=7$

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Updated on: 10-Oct-2022

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