If $a=2$ and $b=-2$ find the value of
$(i)$. $a^2+b^2$
$(ii)$. $a^2+ab+b^2$
$(iii)$. $a^{2}-b^2$

Given:
$(i)$. $a^2+b^2$

$(ii)$. $a^2+ab+b^2$

$(iii)$. $a^{2}-b^2$


To do: To find the value of the given expression if $a=2$ and $b=-2$.

Solution:

$(i)$. $a^2+b^2$

Putting $a=2$ and $b=-2$

$=2^2+(-2)^2$

$=4+4$

$=8$

$(ii)$. $a^2+ab+b^2$

Putting $a=2$ and $b=-2$

$=2^2+2(-2)+(-2)^2$

$=4-4+4$

$=4$

$(iii)$. $a^{2}-b^2$
 
Putting $a=2$ and $b=-2$

$=(2)^2-(-2)^2$

$=4-4$

$=0$

Updated on: 10-Oct-2022

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