If 631x is divisible by 3 , find all possible values of x ,if x is a digit.

Given: 

$631x$ is divisible by 3, where $x$ is a digit.

To do: 

We have to find the possible values of $x$.

Solution:

$631x$ is a multiple of $3$.

Divisibility rule of 3:

Sum of the digits must be divisible by 3.

$\Rightarrow 6 + 3 + 1 + x$ must be divisible by 3.

$\Rightarrow 10 + x$ must be divisible by 3.

If $x=2$, then $10+2=12$ is divisible by 3.

If $x=5$, then $10+5=15$ is divisible by 3.

If $x=8$, then $10+8=18$ is divisible by 3.

Therefore, the possible values of $x$ are $2, 5$ and $8$. 

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Updated on: 10-Oct-2022

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