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If 2 is a zero of the polynomial $p(x)= 4x^2+2x-5a$, then find the value of a.
Given :
The given polynomial is $p(x)= 4x^2+2x-5a$.
2 is the zero of the polynomial $p(x)= 4x^2+2x-5a$.
To find :
We have to find the value of a.
Solution :
The zero of the polynomial is defined as any real value of x, for which the value of the polynomial becomes zero.
Therefore,
Zero of the polynomial $p(2)= 4(2)^2+2(2)-5a=0$
$4(4)+4-5a=0$
$5a=16+4$
$5a=20$
$a=\frac{20}{5}$
$a=4$
The value of a is 4.
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