Identify ‘x’, ‘y’ and ‘z’ in the following reaction : $2KClO_3 (x) \xrightarrow{(y)} 2 KCl (x) + O_2(z)$(a) x = gas ; y = reaction condition, z = gas (b) x = solid ; y = liquid; z = gas (c) x = number of moles of KClO₃ ; y = reaction condition; z = no. of molecules of oxygen. (d) x = physical state of KClO₃ and KCl; y = reaction condition; z = physical state of O₂.

Correct Answer: (d) x =  physical  state  of  KClO3  and  KCl;  y  =  reaction  condition; z = physical state of O2.

Explanation:  $2KClO_3 (x) \xrightarrow{(y)} 2 KCl (x) + O_2(z)$

According to the above equation, x =  physical  state  of  KClO3  and  KCl;  y  =  reaction  condition; z = physical state of O2.

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Updated on: 10-Oct-2022

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