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How many spherical bullets each of $5\ cm$ in diameter can be cast from a rectangular block of metal $11\ dm \times 1\ m \times 5\ dm$?
Given:
Dimensions of the rectangular block are $11\ dm \times 1\ m \times 5\ dm$.
Diameter of spherical bullet $=5\ cm$.
To do:
We have to find the number of spherical bullets that can be cast from the rectangular block.
Solution:
Volume of the rectangular block of metal $V_1 = 11 dm \times 10 dm \times 5 dm$ [$1\ m=10\ dm$]
$= 550\ dm^3$
Radius of the spherical bullet $r=\frac{5}{2} \mathrm{~cm}$
Volume of each bullet $V_{2}=\frac{4}{3} \pi r^{3}$
$=\frac{4}{3} \pi(5)^{3}$
$=\frac{4}{3} \pi \times 125$
$=\frac{500}{3} \times \frac{22}{7}$
$=\frac{11000}{21} \mathrm{~cm}^{3}$
Number of bullets that can be cast $=$ Volume of the rectangular block $\div$ Volume of each bullet
$=\frac{\mathrm{V}_{1}}{\mathrm{~V}_{2}}$
$=\frac{550 \mathrm{dm}^{3}}{\frac{11000}{21} \mathrm{~cm}^{3}}$
$=\frac{550 \times 10 \times 10 \times 10 \times 21}{11000}$ [$1\ dm=10\ cm$]
$=1050$
Therefore, 1050 spherical bullets can be cast from the rectangular block of metal.