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How many $3$ digit numbers are there in between $100$ to $550$?
Given: $3$ digit numbers between $100$ to $550$.
To do: To find the number of $3$ digit numbers between $100$ to $550$.
Solution:
$3$ digit numbers between $1004 to $550$ are: $101\ 102,\ 103,\ .......\ 549$.
It is an A.P., here first term $a=101$, last term $l=549$, common difference $d=1$
As known $l=a+( n-1)d$, here $n$ is the number of terms.
$\Rightarrow 549=101+( n-1)1$
$\Rightarrow n-1=549-101$
$\Rightarrow n-1=448$
$\Rightarrow n=448+1$
$\Rightarrow n=449$
Thus, there are $449$ numbers between $100$ to $550$.
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