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Hameed has built a cubical water tank with lid for his house, with each other edge $1.5\ m$ long. He gets the outer surface of the tank excluding the base, covered with square tiles of side $25\ cm$. Find how much he would spend for the tiles, if the cost of tiles is $Rs.\ 360$ per dozen.
Given:
Hameed has built a cubical water tank with lid for his house, with each other edge $1.5\ m$ long. He gets the outer surface of the tank excluding the base, covered with square tiles of side $25\ cm$.
To do:
We have to find the amount he would spend for the tiles if the cost of tiles is $Rs.\ 360$ per dozen.
Solution:
Edge of the cubical tank $= 1.5\ m$
Area of the walls $= 4 (side)^2$
$= 4(1.5)^2$
$= 4 \times 2.25$
$= 9\ m^2$
Area of the floor $= (1.5)^2$
$= 2.25\ m^2$
Therefore,
Total surface area $= 9 + 2.25$
$= 11.25\ m^2$
Edge of a square tile $= 25\ cm$
$=0.25\ m$
This implies,
Area of a tile $= (0.25)^2$
$= 0.0625\ m^2$
Number of tiles required $=\frac{\text { Total area }}{\text { Area of } 1 \text { tile }}$
$=\frac{11.25}{0.0625}$
$=\frac{1125 \times 10000}{100 \times 625}$
$=180$
Cost of 12 tiles $=Rs.\ 360$
Cost of 180 tiles $=Rs.\ \frac{360 \times 180}{12}$
$= Rs.\ 5400$