Given below is the frequency distribution table regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days.

Find the probability of concentration of sulphur dioxide in the interval 0.12 – 0.16 on any of these days."

Given:

The frequency distribution table regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days.

To do:

We have to find the probability of concentration of sulphur dioxide in the interval 0.12 – 0.16 on any of these days.

Solution:

Total number of days $=30$

Number of days in which concentration of sulphur dioxide is in the interval 0.12 – 0.16 $=2$

We know that,

Probability of an event=$ \frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes}$

Therefore,

Probability that the concentration of sulphur dioxide is in the interval 0.12 – 0.16 $=\frac{2}{30}$

$=\frac{1}{15}$

This implies,

The probability the concentration of sulphur dioxide is in the interval 0.12 – 0.16 is $\frac{1}{15}$.    

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Updated on: 10-Oct-2022

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