Give an example of solving a sum by suitable rearrangement.

Rearrangement is done to make calculations easy.

For example, \( 2 \times 1768 \times 50 \).

In this case, it is difficult to calculate the product of 2 and 1768 and then again multiply that value with 50 to get the final answer.

$2\ \times\ 1768\ \times 50$

Now, we know that product of 2 and 50 is easy to calculate. So, rearranging the digits:

$=\ 1768\ \times\ (2\ \times\ 50)$

$=\ 1768\ \times \ 100$

It is easier to calculate the final value now:

$=\ \mathbf{176800}$

So, the value of the given expression is 176800. 

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Updated on: 10-Oct-2022

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