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$ =\frac{\frac{50}{3}-\frac{200}{9}}{5} $
"
Given: $\frac{\frac{50}{3} \ -\ \frac{200}{9}}{5}$
To find: We have to evaluate the value of $\frac{\frac{50}{3} \ -\ \frac{200}{9}}{5}$.
Solution: $\frac{\frac{50}{3} \ -\ \frac{200}{9}}{5}$
$ \begin{array}{l}
The\ LCM\ of\ 3\ and\ 9\ is\ 9,\ Therefore,\\
\end{array}$
= $\frac{\frac{50}{3} \ -\ \frac{200}{9}}{5} \ =\ \frac{\frac{50\ \times \ 3\ -\ 200}{9}}{5}$
= $\frac{150\ -\ 200}{9\ \times \ 5}$
= $\frac{-50}{45}$
= $\frac{-10}{9}$
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