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$\frac{7}{9} \ \times \ \frac{-1}{2} \ -\ \left(\frac{7}{9}\right) \ \ \times \ \left(\frac{-3}{2}\right)$
Given: $\frac{7}{9} \ \times \ \frac{-1}{2} \ -\ \left(\frac{7}{9}\right) \ \ \times \ \left(\frac{-3}{2}\right)$
To find: We have to find the value of $\frac{7}{9} \ \times \ \frac{-1}{2} \ -\ \left(\frac{7}{9}\right) \ \ \times \ \left(\frac{-3}{2}\right)$
Solution:
$\frac{7}{9} \ \times \ \frac{-1}{2} \ -\ \left(\frac{7}{9}\right) \ \ \times \ \left(\frac{-3}{2}\right)$
$Taking\ \frac{7}{9} \ common,\ we\ get\ that$
$=\ \frac{7}{9} \times \ \left(\frac{-1}{2} \ -\ \left(\frac{-3}{2}\right)\right)$
$=\ \frac{7}{9} \times \ \left(\frac{-1}{2} \ +\ \frac{3}{2}\right)(( -\ \times \ -) \ =\ +)$
$=\ \frac{7}{9} \times \ \left(\frac{3-1}{2}\right)$
$=\ \frac{7}{9} \times \ \left(\frac{2}{2}\right) \ =\ \frac{7}{9} \times \ 1$
$=\ \frac{7}{9}$