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Find x if  2x÷3+1 = 7x÷15+3
Given: $ \frac{2x}{3} + 1 = \frac{7x}{15} + 3$
To find: $x$
Solution:
$ \frac{2x}{3} + 1 = \frac{7x}{15} + 3$
Transposing $ \frac{7x}{15}$ to the LHS and 1 to the RHS:
$ \frac{2x}{3} - \frac{7x}{15} = 3 - 1 = 2$
=>$ \frac{10x - 7x}{15} = 2$
=> $\frac{3x}{15} = 2$
=> $ x = 10$
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