Find three consecutive natural numbers such that the sum of the first and second is 15 more than the third.

Given :

The sum of the first and second natural numbers is 15 more than the third.

To do :

We have to find the numbers.

Solution :

Let the first natural number be x.

Then the next two natural numbers are $x+1$ and $x+2$.

$x+(x+1)= (x+2)+15$

$2x+1=x+17$

$2x-x=17-1$

$x=16$

Other numbers are

$16+1=17$ and $16+2=18$

Therefore, the three natural numbers are $16, 17, 18$.

Tutorialspoint

Updated on: 10-Oct-2022

143 Views

Kickstart Your Career

Get certified by completing the course

Get Started