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Find three consecutive even numbers such that sum of 1st and last numbers exceed the second number by 10.
To do: Find three consecutive even numbers such that sum of 1st and last numbers exceed the second number by 10.
Solution:
Let the numbers be $a, a +2 \ and \ a + 4$
According to question, sum of $a$ and $a+ 4$ exceeds $a+2$ by 10
$a + a + 4 = a + 2 + 10$
=> $2a + 4 = a + 12$
=> $2a - a = 12 - 4$
=>$ a = 8$
Therefore,
First number = $8$
Second number = $8+2 = 10$
Third number is $a+4 = 12$
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