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Find the volume of a sphere whose radius is
(i) $ 7 \mathrm{~cm} $
(ii) $ 063 \mathrm{~m} $.
Given:
Radius of a sphere is
(i) \( 7 \mathrm{~cm} \)
(ii) \( 063 \mathrm{~m} \).
To do:
We have to find the volumes of the sphere in each case.
Solution:
We know that,
Volume of a sphere of radius $r$ is $\frac{4}{3} \pi r^3$
Therefore,
(i) Volume of the sphere of radius $7\ cm= \frac{4}{3} \pi (7)^3$
$=\frac{4}{3} \times \frac{22}{7} \times (7)^3$
$= \frac{4312}{3}\ cm^3$
Hence, the volume of the sphere is $\frac{4312}{3}\ cm^3$
(ii) Volume of the sphere of radius $0.63\ m= \frac{4}{3} \pi (0.63)^3$
$=\frac{4}{3} \times \frac{22}{7} \times (0.63)^3$
$=\frac{4}{3} \times 22 \times (0.63)^2 \times 0.09$
$=88 \times 0.3969 \times 0.03$
$= 1.0478\ m^3$
$\approx 1.05\ m^3$
Hence, the volume of the sphere is $1.05\ m^3$.
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