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Find the volume of a cube, one face of which has an area of $64\ m^2$.
Given :
Area of the face of a cube $=64\ m^2$.
To do :
We have to find the volume of the cube.
Solution :
Let the side of the cube be $s$ m.
Area of the face of a cube $= s^2$ sq. m.
$64\ m^2 = s^2\ m^2$
$8 \times 8= s^2$
$s = 8\ m$.
The volume of a cube of side $s = s^3\ m^3$.
The volume of the given cube $= (8)^3\ m^3$
$= 512\ m^3$
Therefore, the volume of the cube is $512\ m^3$.
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