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Find the value of y in the following figure.
"
Given:
$\angle BAC=80^o$, $\angle CAB=52^o$.
To do:
We have to find the value of y.
Solution:
We know that,
The exterior angle theorem states that the measure of each exterior angle of a triangle is equal to the sum of the opposite and non-adjacent interior angles.
Therefore,
$80^o+52^o=y$
$y=132^o$
The value of y is $132^o$.
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