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Find the value Of $x$ $ \frac{1}{2}-\frac{1}{3}(x-1)+2=0 $
Given: $ \frac{1}{2}-\frac{1}{3}(x-1)+2=0 $
To do: Find $x$.
Solution:
$ \frac{1}{2}-\frac{1}{3}(x-1)+2=0 $
$ \frac{1}{2}-\frac{1}{3}x +\frac{1}{3}+2=0$
$\frac{1}{2}+\frac{1}{3}+2=\frac{1}{3}x$
LCM of 2 and 3 is 6
$\frac{3+2+6}{6}=\frac{1}{3}x$
$\frac{11}{6}=\frac{1}{3}x$
Cross multiplying 3 to LHS
$3\frac{11}{6}=x$
$\frac{11}{2}=x$
Therefore, the value of $x$ is $\frac{11}{2}$
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