Find the value of x:
$\frac{x\ -\ 5}{2} \ +\ \frac{2}{5} \ -\ \frac{2x}{7} \ =\ 1$
Given: $\frac{x\ -\ 5}{2} \ +\ \frac{2}{5} \ -\ \frac{2x}{7} \ =\ 1$
To find: Here we have to find the value of x in the given expression.
Solution:
$\frac{x\ -\ 5}{2} \ +\ \frac{2}{5} \ -\ \frac{2x}{7} \ =\ 1$
$\frac{x\ -\ 5}{2} \ -\ \frac{2x}{7} \ =\ 1\ -\ \frac{2}{5}$
$\frac{7( x\ -\ 5) \ -\ 2( 2x)}{14} \ =\ \frac{5\ -\ 2}{5}$
$\frac{7x\ -\ 35\ -\ 4x}{14} \ =\ \frac{3}{5}$
$\frac{3x\ -\ 35}{14} \ =\ \frac{3}{5}$
$3x\ -\ 35\ =\ \frac{3\ \times \ 14}{5}$
$3x\ -\ 35\ =\ \frac{42}{5}$
$3x\ =\ \frac{42}{5} \ +\ 35$
$3x\ =\ \frac{42\ +\ 175}{5}$
$3x\ =\ \frac{217}{5}$
$x\ =\ \frac{217}{5\ \times \ 3}$
$\mathbf{x\ =\ \frac{217}{15}}$
So, value of x is $\frac{217}{15}$.
Related Articles
- Find the value of $x$ if:$\frac{2x\ +\ 7}{5} \ -\ \frac{3x\ +\ 11}{2} \ =\ \frac{2x\ +\ 8}{3} \ -\ 5$
- If $\frac{2 x}{5}-\frac{3}{2}=\frac{x}{2}+1$, find the value of $x$.
- Find the value of $x$$\frac{x+2}{2}- \frac{x+1}{5}=\frac{x-3}{4}-1$
- Find the value of $x$:$\frac{7}{2} x-\frac{5}{2} x=\frac{20 x}{3}+10$.
- Find the value of x:$ 2 x - \frac{2}{5} = \frac{3}{5} - x$
- If $x - \frac{1}{x} = \sqrt{5}$, find the value of $x^2 + \frac{1}{x^2}$
- If $\frac{x-3}{5}-2=\frac{2 x}{5}$, find the value of $x$.
- Solve the equation $\frac{2x}{5} - \frac{3}{5} = \frac{x}{2}+1$.
- Add the following algebraic expressions(i) \( 3 a^{2} b,-4 a^{2} b, 9 a^{2} b \)(ii) \( \frac{2}{3} a, \frac{3}{5} a,-\frac{6}{5} a \)(iii) \( 4 x y^{2}-7 x^{2} y, 12 x^{2} y-6 x y^{2},-3 x^{2} y+5 x y^{2} \)(iv) \( \frac{3}{2} a-\frac{5}{4} b+\frac{2}{5} c, \frac{2}{3} a-\frac{7}{2} b+\frac{7}{2} c, \frac{5}{3} a+ \) \( \frac{5}{2} b-\frac{5}{4} c \)(v) \( \frac{11}{2} x y+\frac{12}{5} y+\frac{13}{7} x,-\frac{11}{2} y-\frac{12}{5} x-\frac{13}{7} x y \)(vi) \( \frac{7}{2} x^{3}-\frac{1}{2} x^{2}+\frac{5}{3}, \frac{3}{2} x^{3}+\frac{7}{4} x^{2}-x+\frac{1}{3} \) \( \frac{3}{2} x^{2}-\frac{5}{2} x-2 \)
- Solve the following quadratic equation by factorization: $\frac{x-1}{2x+1}+\frac{2x+1}{x-1}=\frac{5}{2}, x ≠-\frac{1}{2},1$
- Take away:(i) \( \frac{6}{5} x^{2}-\frac{4}{5} x^{3}+\frac{5}{6}+\frac{3}{2} x \) from \( \frac{x^{3}}{3}-\frac{5}{2} x^{2}+ \) \( \frac{3}{5} x+\frac{1}{4} \)(ii) \( \frac{5 a^{2}}{2}+\frac{3 a^{3}}{2}+\frac{a}{3}-\frac{6}{5} \) from \( \frac{1}{3} a^{3}-\frac{3}{4} a^{2}- \) \( \frac{5}{2} \)(iii) \( \frac{7}{4} x^{3}+\frac{3}{5} x^{2}+\frac{1}{2} x+\frac{9}{2} \) from \( \frac{7}{2}-\frac{x}{3}- \) \( \frac{x^{2}}{5} \)(iv) \( \frac{y^{3}}{3}+\frac{7}{3} y^{2}+\frac{1}{2} y+\frac{1}{2} \) from \( \frac{1}{3}-\frac{5}{3} y^{2} \)(v) \( \frac{2}{3} a c-\frac{5}{7} a b+\frac{2}{3} b c \) from \( \frac{3}{2} a b-\frac{7}{4} a c- \) \( \frac{5}{6} b c \)
- Find the following products:\( \frac{7}{5} x^{2} y\left(\frac{3}{5} x y^{2}+\frac{2}{5} x\right) \)
- If \( x-\frac{1}{x}=5 \), find the value of(a) \( x^{2}+\frac{1}{x^{2}} \)(b) \( x^{4}+\frac{1}{x^{4}} \)
- Take away:\( \frac{6}{5} x^{2}-\frac{4}{5} x^{3}+\frac{5}{6}+\frac{3}{2} x \) from \( \frac{x^{3}}{3}-\frac{5}{2} x^{2}+\frac{3}{5} x+\frac{1}{4} \)
- Simplify each of the following products:\( (\frac{x}{2}-\frac{2}{5})(\frac{2}{5}-\frac{x}{2})-x^{2}+2 x \)
Kickstart Your Career
Get certified by completing the course
Get Started