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Find the value of x.
$\frac{2x}{3} \ +\ 1\ =\ \frac{7x}{15} \ +\ 3$
Given: $\frac{2x}{3} \ +\ 1\ =\ \frac{7x}{15} \ +\ 3$
To find: We need to find the value of $\frac{2x}{3} \ +\ 1\ =\ \frac{7x}{15} \ +\ 3$
Solution:
$\frac{2x}{3} \ +\ 1\ =\ \frac{7x}{15} \ +\ 3$$\Longrightarrow \ \ \frac{2x}{3} \ -\ \frac{7x}{15} \ =\ 2$
$\Longrightarrow \ \frac{10x}{15} \ -\ \frac{7x}{15} \ =\ 2$
$\Longrightarrow \ \frac{3x}{15} =\ 2$
$\Longrightarrow \ x\ =\ \frac{30}{3} \ =\ 10$
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