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Find the value of \( x \) in each of the following:
\( \quad 2 \sin 3 x=\sqrt{3} \)
Given:
\( \quad 2 \sin 3 x=\sqrt{3} \)
To do:
We have to find the value of \( x \).
Solution:
$2 \sin 3 x=\sqrt{3}$
$\Rightarrow \sin 3 x=\frac{\sqrt{3}}{2}$
We know that,
$\sin 60^{\circ}=\frac{\sqrt3}{2}$
$\Rightarrow \sin 3 x=\frac{\sqrt{3}}{2}$
$\Rightarrow \sin 3 x=\sin 60^{\circ}$
Comparing on both sides, we get,
$3x=60^{\circ}$
$x=\frac{60^{\circ}}{3}$
$x=20^{\circ}$
Hence, the value of $x$ is $20^{\circ}$.
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