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Find the value of $x$ if $(3^{x+2}-9)\div 8 = 9$
Given : $(3^{x+2}-9)\div 8 = 9$
To do: We have to find $x$
Solution:
$(3^{x+2}-9)\div 8 = 9$
$\frac{3^{x+2}-9}{8}=9$
$3^{x+2}-9=9\times8$
$3^{x+2}=72+9$
$3^x\times3^2=81$
$3^x\times9=81$
$3^x=\frac{81}{9}$
$3^x=9$
$3^2=3^2$
Therefore the value of $x \ is \ 2$
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