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Find the value of t, if $0.1(t-3)=0.15(t-4)$​.
Given:
$0.1(t-3) =0.15(t-4)$
To do:
We have to find the value of t.
Solution:
$0.1(t-3) =0.15(t-4)$
$0.1(t) - 0.1(3) = 0.15(t) - 0.15(4)$
$0.1t - 0.3 = 0.15t - 0.6$
$(0.15-0.1)t=0.6-0.3$
$0.05t = 0.3$
$t = \frac{0.3}{0.05}$
$t = \frac{30}{5}$
$t= 6$
The value of t is 6.
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