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Find the value of:
$\left( 3^{0} \ +\ 4^{-1}\right) \ \times \ 2^{2}$
Given: $\left( 3^{0} \ +\ 4^{-1}\right) \ \times \ 2^{2}$.
To find: Here we have to find the value of the given expression $\left( 3^{0} \ +\ 4^{-1}\right) \ \times \ 2^{2}$.
Solution:
$\left( 3^{0} \ +\ 4^{-1}\right) \ \times \ 2^{2}$
$=\ \left( 1\ +\ \frac{1}{4}\right) \ \times \ 4$
$=\ \left(\frac{4\ +\ 1}{4}\right) \ \times \ 4$
$=\ \left(\frac{5}{4}\right) \ \times \ 4$
$=\ \mathbf{5}$
So, the answer is 5.
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