Find the value of \( k \), if \( x=2, y=1 \) is a solution of the equation \( 2 x+3 y=k \)
Given:
$x=2$, $y=1$ is the solution of the equation $2x+3y=k$.
To do:
We have to find the value of $k$.
Solution:
According to the question,
$x=2$, $y=1$ is the solution of the equation $2x+3y=k$.
Now,
Let us substitute $x=2$, $y=1$ in the equation $2x+3y=k$
We get,
$2(2)+3(1)=k$
This implies,
$4+3=k$
$7=k$
Therefore,
$k=7$
The value of $k$ is $7$.
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