Find the value of
$3 x^{2}-2 y^{2}$
if x=-2 and y=2
Given: If $x = -2$ and $y = 2$
To find :The value of $3x^{2} - 2y^{2}$
Answer:
$ x = -2 and y = 2$
Substituting these values in the expression below
$3x^{2} - 2y^{2}$
= $3(-2)^{2} - 2(2)^{2}$
= 12 - 8 = 4
=$3x^{2} - 2y^{2} = 4$ when x = -2 and y = 2
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