Find the value of:
(a) $ 4.9 \p 0.07 $
(b) $ 26.4 \p 2.4 $
Given:
(a) \( 4.9 \div 0.07 \)
(b) \( 26.4 \div 2.4 \)
To do:
We have to find the value of:
(a) \( 4.9 \div 0.07 \)
(b) \( 26.4 \div 2.4 \)
Solution:
(a) $4.9\ \div\ 0.07$
$=\ \frac{4.9\times100}{0.07\times100}$
$=\frac{490}{7}$
$=70$
(b) $26.4\ \div\ 2.4$
$=\ \frac{26.4\times10}{2.4\times10}$
$=\frac{264}{24}$
$=11$
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