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Find the value of $4m^2 n^2 \times 7m^3$ when $m= \frac{-1}{2}$ and $n= 4$.
Given:
Given expression is $4m^2 n^2 \times 7m^3$.
To do:
We have to find the value of the given expression when $m= \frac{-1}{2}$ and $n= 4$.
Solution:
Substituting the given values, we get,
$4m^2 n^2 \times 7m^3=[4(\frac{-1}{2})^2 \times (4)^2] \times [7(\frac{-1}{2})^3]$
$=[4(\frac{1}{4}) \times 16] \times [7(\frac{-1}{8})]$
$=(1\times16) \times (\frac{-7}{8})$
$=16\times\frac{-7}{8}$
$=2\times(-7)$
$=-14$
The value of $4m^2 n^2 \times 7m^3$ when $m= \frac{-1}{2}$ and $n= 4$ is $-14$.
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