Find the value in the blank.$\frac{6}{17} = \frac{18}{...}$
Given :
The given expression is $\frac{6}{17} = \frac{18}{...}$.
To do :
We have to find the value in the blank.
Solution :
Let the required number be $=$ a.
$\frac{6}{17} = \frac{18}{a}$
$6a = 18 \times 17$
Transpose 6 to the opposite side,
$a = \frac{18 \times 17}{6}$.
$a = 3 \times 17$ $[3 \times 6 = 18]$
$a = 51$
So, the required number is 51.
Related Articles
- Solve the following.$\frac{6}{17}=\frac{18}{...}$
- Which of the following are like fractions $\frac{6}{17}, \frac{18}{7}, \frac{17}{9}, \frac{7}{17}, \frac{21}{19}, \frac{32}{17}, \frac{12}{17}$.
- Find the sum:$( \frac{4}{17}+\frac{19}{17})$
- Solve:$\frac{17}{9}-\frac{2}{15}+\frac{11}{18}$
- Fill in the blank: $( \frac{15}{7}\times \frac{-21}{10}\times \frac{-5}{6})$=$( \frac{-21}{10}\times\frac{-5}{6})\times$____
- Find the value of $x$$\frac{8}{-3}= \frac{x}{6}$
- Find the value of:\( 2 \frac{4}{8}+2 \frac{6}{8} \)
- If $\frac{x}{4}=\frac{3}{6}$, find the value of $x$.
- From the sum of $\frac{-18}{51}$ and $\frac{2}{17}$ subtract the sum of $\frac{1}{85}$ and $\frac{-2}{5}$
- Among $\frac{-6}{11},\ \frac{6}{13},\ \frac{-6}{7},\ \frac{-6}{8}$, find the greatest number.
- Find:$(i)$. $\frac{7}{24\ }- \frac{17}{36}$$(ii)$. $\frac{5}{63}-\ (-\frac{6}{21})$$(iii)$. $-\frac{6}{13}\ -\ (-\frac{7}{15})$$(iv)$. $-\frac{3}{8}-\frac{7}{11}$$(v)$. $-2\frac{1}{9}\ -\ 6$
- Find the value of the following:$\sqrt{\frac{4}{6}}$
- If $\frac{n}{4}-5=\frac{n}{6}+\frac{1}{2}$, find the value of $n$.
- Find the value of x from the following expression.$\frac{x}{10} + \frac{x+1}{17} + \frac{x+2}{26} = 10$
- Pick out four equivalent fractions from the group$\frac{1}{2}, \frac{3}{6}, \frac{5}{6}, \frac{8}{17}, \frac{2}{4}, \frac{111}{222}, \frac{2}{3}$
Kickstart Your Career
Get certified by completing the course
Get Started