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Find the sum of first 8 multiples of 3.
Given: First 8 multiples of 3.
To do: To find the sum of first 8 multiples of 3.
Solution:
First 8 multiples of 3 are
3, 6, 9, 12, 15, 18, 21, 24
The above sequence is an A.P.
Whose first term, $a=3$, common difference, $d = 3$ and last term $l=24$
As known sum first n terms of an A.P.$=\frac{n}{2}( a+l)$
$=\frac{8}{2}( 3+24)$
$=4( 27)$
$=108$
Therefore sum of first 8 multiples of 3 is 108.
 
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