Find the smallest square number divisible by each one of them number 8,9and 10
Given: Numbers $8,\ 9$ and $10$.
To do: To find the smallest square number divisible by each one of the number $8,\ 9$ and $10$.
Solution:
L.C.M. of $8,\ 9,\ 10$ is $2\times2\times2\times3\times3\times5=360$
Since $2$ and $5$ are not in pairs multiply by $2$ and $5$ to make it a perfect square.
The required number$=360\times2\times5=3600$
The smallest square number divisible by $8,\ 9,\ 10=3600$.
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